標題:
Gauss' Theorem
發問:
R=(x,y,z) r = (x^2 + y^2 + z^2)^(1/2) i): Show that (Δ ? F) = 0 if F has the form kR/r^3 where r not equal to 0 (ii): Show that if F has the form kR/r^3 ∫∫ F ? ndS = 4pi where the boundary is the sphere of radius 1 center at (0,0,0) 更新: Δ = nabla
最佳解答:
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(i) R=(x,y,z) ?. F =k[?/?x(x/r^3)+?/?x(x/r^3)+?/?x(x/r^3)] =k{[r^3-x3r^2(x/r)]/r^6+[r^3-y3r^2(y/r)]/r^6+[r^3-z3r^2(z/r)]/r^6} =k{[r^3-3x^2r]/r^6+[r^3-3y^2r]/r^6+[r^3-3z^2r]/r^6} =k{[3r^3-3r^3]/r^6} =0 (ii) Since n=(x/r,y/r,z/r), F ? n=(x^2+y^2+z^2)/r^4 ∫∫ F ? ndS =∫∫(x^2+y^2+z^2)/r^4 dS =r^(-2) ∫∫ dS =4 pi [The boundary is the sphere of radius r center at (0,0,0)] ∫∫ F ? ndS
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