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急急急```有d F2數唔識
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1a) y^3+2+2y^2+y =2(1+y^2)+y(1+y^2) =(2+y)(1+y^2) 1b) uv-u-v^2+v =u(1-v)+v(1-v) =(u+v)(1-v) 2a) (a+b)^2-2(a+b) =(a+b)(a+b-2) 2b)Sorry.I dun no whether it's 16(x+y)^(2z) or (16(x+y)^2)z 3) 2u(a-b-c)-3v(b+c-a) =2au-2bu-2cu-3bv-3cv+3av =a(2u+3v)-b(2u+3v)-c(2u+3v) =(a-b-c)(2u+3v) 4) 6(2x-y)(3a-b)-2(y-2x)(b-3a) =6(2x-y)(3a-b)-2(-(2x-y))(-(3a-b)) =4(2x-y)(3a-b) 5) Sorry.I've no idea... 6) Sorry.I dun no whether it's 12(h-k)m^(2n) (12(h-k)m^2)n
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急急急```有d F2數唔識
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Factorize the following expression 1a) y^3+2+2y^2+y 1b) uv-u-v^2+v 2a) (a+b)^2-2(a+b) 2b) 24(x+y)z^2+16(x+y)^2z-8(x+y)z^3 3) 2u(a-b-c)-3v(b+c-a) 4) 6(2x-y)(3a-b)-2(y-2x)(b-3a) 5) w/4x+ w/6+ 3/2xz+ y/z 6) -9(h-k)mn^3-15(h-k)mn+12(h-k)m^2n ****第5條既w/4x即係w over 4x thx!最佳解答:
1a) y^3+2+2y^2+y =2(1+y^2)+y(1+y^2) =(2+y)(1+y^2) 1b) uv-u-v^2+v =u(1-v)+v(1-v) =(u+v)(1-v) 2a) (a+b)^2-2(a+b) =(a+b)(a+b-2) 2b)Sorry.I dun no whether it's 16(x+y)^(2z) or (16(x+y)^2)z 3) 2u(a-b-c)-3v(b+c-a) =2au-2bu-2cu-3bv-3cv+3av =a(2u+3v)-b(2u+3v)-c(2u+3v) =(a-b-c)(2u+3v) 4) 6(2x-y)(3a-b)-2(y-2x)(b-3a) =6(2x-y)(3a-b)-2(-(2x-y))(-(3a-b)) =4(2x-y)(3a-b) 5) Sorry.I've no idea... 6) Sorry.I dun no whether it's 12(h-k)m^(2n) (12(h-k)m^2)n
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