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計圓入面ge角度..........help
發問:
1.http://img301.imageshack.us/img301/9741/img0002du9.jpg 依題計X 2.http://img301.imageshack.us/img301/4679/img0003ps0.jpg 依題計周界喔.... 更新: 個條問題係這樣o
最佳解答:
1.I think you have miss some details in the question 2.as MN, NC, CB, BM are tangent of the circle at P,S, R, Q respectively, so PN=NS, SC=CR RB=BQ QM=MP first as M,N are mid-pt of AB,AC reapcetively, MN=BC/2 (mid-pt thm) MN=9cm MP+PN=MN =9cm so QM+NS = 9cm BR+RC = BC=18cm so BQ+SC =18cm MB+NC =MQ+QB+NS+SC =( QM+NS) +(BQ+SC ) =9+18=27cm AM=MB AN=NC AM+AN=MB+NC =27cm so the perimeter of triangle ABC=27+27+18=72cm
計圓入面ge角度..........help
發問:
1.http://img301.imageshack.us/img301/9741/img0002du9.jpg 依題計X 2.http://img301.imageshack.us/img301/4679/img0003ps0.jpg 依題計周界喔.... 更新: 個條問題係這樣o
最佳解答:
1.I think you have miss some details in the question 2.as MN, NC, CB, BM are tangent of the circle at P,S, R, Q respectively, so PN=NS, SC=CR RB=BQ QM=MP first as M,N are mid-pt of AB,AC reapcetively, MN=BC/2 (mid-pt thm) MN=9cm MP+PN=MN =9cm so QM+NS = 9cm BR+RC = BC=18cm so BQ+SC =18cm MB+NC =MQ+QB+NS+SC =( QM+NS) +(BQ+SC ) =9+18=27cm AM=MB AN=NC AM+AN=MB+NC =27cm so the perimeter of triangle ABC=27+27+18=72cm
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