thhzpvx的部落格

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呢條數點計(5)

發問:

5[2(y-4.2)+y-1]=y-5 諗唔到

最佳解答:

5[2(y-4.2)+y-1]=y-5 5(2y-8.4+y-1)=y-5 10y-42+5y-5=y-5 10y+5y-y=-5+5+42 14y=42 y=42/14 y=3 Answer: 3 2007-09-27 22:00:33 補充： Don't copy me!

其他解答:

5[2(y-4.2)+y-1] = y-5 5[(2y-8.4)+y-1] = y-5 5[2y-8.4+y-1] = y-5 10y-42+5y-5 = y-5 10y-42+5y-5 = y-5 10y+ 5y-y = (-5)+42+5 15y-y = 37+5 14y = 42 14y÷14 = 42÷14 y = 3 ..........ok.......|||||5[2(y-4.2)+y-1]=y-5 5[2y-8.4+y-1]=y-5 5[2y+y-8.4-1]=y-5 5[3y-9.4]=y-5 15y-47=y-5 15y-y=-5+47 14y=42 y=3|||||5[2(y-4.2)+y-1]=y-5 5(2y-8.4+y-1) =y-5 5(3y-9.4) =y-5 15y-47=y-5 14y=42 y=3|||||5[2(y-4.2)+y-1]=y-5 5(2y-8.4+y-1)=y-5 10y-42+5y-5=y-5 10y+5y-y=-5+5+42 14y=42 y=42/14 y=3 Answer: 3|||||5[2(y-4.2)+y-1]=y-5 5(2y-8.4+y-1)=y-5 10y-42+5y-5=y-5 10y+5y-y=-5+5+42 14y=42 y=42/14 y=3|||||5[2(y-4.2)+y-1]=y-5 5[2y-8.4+y-1]=y-5 10y-42+5y-5=y-5 10y+5y-y=-5+42+5 14y=42 y=3|||||5[2(y-4.2)+y-1]=y-5 5(2y-8.4+y-1)=y-5 10y-42+5y-5=y-5 10y+5y-y=-5+5+42 14y=42 y=42/14 y=3 Answer: 3|||||??? ar