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標題:
maths questions?
發問:
3z-2分之7z+2-3z分之z+4 要有式啊！ 好急
最佳解答:
7z/(3z - 2) + (z + 4)/(2 - 3z) = 7z/(3z - 2) - (z + 4)/(3z - 2) = [7z - (z + 4)] / (3z - 2) = (7z - z - 4) / (3z - 2) = (6z - 4) / (3z - 2) = 2(3z - 2) / (3z - 2) = 2
7z/(3z-2)+[(z+4)/2-3z] =7z/(3z-2)+[(z+4)/-(3z-2)] =7z/(3z-2)-[(z+4)/3z-2] =(7z-z-4)/(3z-2) =(6z-4)/(3z-2) =2(3z-2)/(3z-2) =2|||||no..........................................
maths questions?
發問:
3z-2分之7z+2-3z分之z+4 要有式啊！ 好急
最佳解答:
7z/(3z - 2) + (z + 4)/(2 - 3z) = 7z/(3z - 2) - (z + 4)/(3z - 2) = [7z - (z + 4)] / (3z - 2) = (7z - z - 4) / (3z - 2) = (6z - 4) / (3z - 2) = 2(3z - 2) / (3z - 2) = 2
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其他解答:7z/(3z-2)+[(z+4)/2-3z] =7z/(3z-2)+[(z+4)/-(3z-2)] =7z/(3z-2)-[(z+4)/3z-2] =(7z-z-4)/(3z-2) =(6z-4)/(3z-2) =2(3z-2)/(3z-2) =2|||||no..........................................
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